mpc_python_learn/notebooks/numericalJacobian.ipynb

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{
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"cell_type": "markdown",
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"# Compute the jacobian numerically\n",
"\n",
"link: --> http://www.maths.lth.se/na/courses/FMN081/FMN081-06/lecture7.pdf\n",
"\n",
"Often the Jacobian is not **analytically** available and it has to be computed numerically.\n",
"It can be computed column wise by finite differences:\n",
"\n"
]
},
{
"cell_type": "code",
"execution_count": 1,
"metadata": {},
"outputs": [],
"source": [
"import numpy as np\n",
"\n",
"# #CONTINUOUS\n",
"# def f(x,u):\n",
"# \"\"\"\n",
"# :param x:\n",
"# :param u:\n",
"# \"\"\"\n",
"# xx = x[0]\n",
"# xy = x[1]\n",
"# v = x[2]\n",
"# theta =x[3]\n",
" \n",
"# a = u[0]\n",
"# delta = u[1]\n",
" \n",
"# L=0.3\n",
" \n",
"# #vector of ackerman equations\n",
"# return np.array([\n",
"# np.cos(theta)*v,\n",
"# np.sin(theta)*v,\n",
"# a,\n",
"# v*np.arctan(delta)/L\n",
"# ])\n",
"\n",
"#DISCRETE\n",
"def f(x, u, dt=0.1):\n",
" \"\"\"\n",
" :param x:\n",
" :param u:\n",
" \"\"\"\n",
" xx = x[0]\n",
" xy = x[1]\n",
" v = x[2]\n",
" theta =x[3]\n",
" \n",
" a = u[0]\n",
" delta = u[1]\n",
" \n",
" L=0.3\n",
" \n",
" #vector of ackerman equations\n",
" return np.array([\n",
" xx + np.cos(theta)*v*dt,\n",
" xy + np.sin(theta)*v*dt,\n",
" v + a*dt,\n",
" theta + v*np.arctan(delta)/L*dt\n",
" ])\n",
"\n",
"def Jacobians(f,x,u,epsilon=1e-4):\n",
" \"\"\"\n",
" :param f:\n",
" :param x:\n",
" :param u:\n",
" \"\"\"\n",
" \n",
" jac_x = np.zeros((4,4))\n",
" jac_u = np.zeros((4,2))\n",
" \n",
" perturb_x = np.eye(4)*epsilon\n",
" perturb_u = np.eye(2)*epsilon\n",
" \n",
" #each row is state vector where one variable has been perturbed\n",
" x_perturbed_plus = np.tile(x,(4,1))+perturb_x\n",
" x_perturbed_minus = np.tile(x,(4,1))-perturb_x\n",
" \n",
" #each row is state vector where one variable has been perturbed\n",
" u_perturbed_plus = np.tile(u,(2,1))+perturb_u\n",
" u_perturbed_minus = np.tile(u,(2,1))-perturb_u\n",
" \n",
" for i in range(x.shape[0]):\n",
" \n",
" #each coloumn of the jac is given by perturbing a variable\n",
" jac_x[:,i]= (f(x+perturb_x[i,:], u)-f(x-perturb_x[i,:], u))/2*epsilon\n",
" \n",
" for i in range(u.shape[0]):\n",
" \n",
" #each coloumn of the jac is given by perturbing a variable\n",
" jac_u[:,i]= (f(x, u+perturb_u[i,:])-f(x, u-perturb_u[i,:]))/2*epsilon\n",
"\n",
" return jac_x, jac_u\n",
" "
]
},
{
"cell_type": "code",
"execution_count": 2,
"metadata": {},
"outputs": [
{
"data": {
"text/plain": [
"(array([[1.00000000e-08, 0.00000000e+00, 1.00000000e-09, 0.00000000e+00],\n",
" [0.00000000e+00, 1.00000000e-08, 0.00000000e+00, 9.99999998e-10],\n",
" [0.00000000e+00, 0.00000000e+00, 1.00000000e-08, 0.00000000e+00],\n",
" [0.00000000e+00, 0.00000000e+00, 6.57985199e-10, 1.00000000e-08]]),\n",
" array([[0.0000000e+00, 0.0000000e+00],\n",
" [0.0000000e+00, 0.0000000e+00],\n",
" [1.0000000e-09, 0.0000000e+00],\n",
" [0.0000000e+00, 3.2051282e-09]]))"
]
},
"execution_count": 2,
"metadata": {},
"output_type": "execute_result"
}
],
"source": [
"#starting condition\n",
"x=np.array([0,0,1,0])\n",
"u=np.array([1,0.2])\n",
"\n",
"Jacobians(f,x,u)"
]
}
],
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