163 lines
6.5 KiB
C++
163 lines
6.5 KiB
C++
/**
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* @file ActiveSetSolver.h
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* @brief Abstract class above for solving problems with the abstract set method.
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* @author Ivan Dario Jimenez
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* @author Duy Nguyen Ta
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* @date 1/25/16
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*/
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#pragma once
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#include <gtsam/linear/GaussianFactorGraph.h>
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#include <boost/range/adaptor/map.hpp>
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namespace gtsam {
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class ActiveSetSolver {
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public:
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typedef std::vector<std::pair<Key, Matrix> > TermsContainer;
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protected:
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KeySet constrainedKeys_; //!< all constrained keys, will become factors in dual graphs
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GaussianFactorGraph baseGraph_; //!< factor graphs of cost factors and linear equalities.
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//!< used to initialize the working set factor graph,
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//!< to which active inequalities will be added
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VariableIndex costVariableIndex_, equalityVariableIndex_,
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inequalityVariableIndex_; //!< index to corresponding factors to build dual graphs
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public:
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/// Create a dual factor
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virtual JacobianFactor::shared_ptr createDualFactor(Key key,
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const InequalityFactorGraph& workingSet,
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const VectorValues& delta) const = 0;
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/// Collect the Jacobian terms for a dual factor
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template <typename FACTOR>
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TermsContainer collectDualJacobians(
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Key key, const FactorGraph<FACTOR>& graph,
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const VariableIndex& variableIndex) const {
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TermsContainer Aterms;
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if (variableIndex.find(key) != variableIndex.end()) {
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BOOST_FOREACH (size_t factorIx, variableIndex[key]) {
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typename FACTOR::shared_ptr factor = graph.at(factorIx);
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if (!factor->active()) continue;
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Matrix Ai = factor->getA(factor->find(key)).transpose();
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Aterms.push_back(std::make_pair(factor->dualKey(), Ai));
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}
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}
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return Aterms;
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}
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/**
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* The goal of this function is to find currently active inequality constraints
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* that violate the condition to be active. The one that violates the condition
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* the most will be removed from the active set. See Nocedal06book, pg 469-471
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*
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* Find the BAD active inequality that pulls x strongest to the wrong direction
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* of its constraint (i.e. it is pulling towards >0, while its feasible region is <=0)
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*
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* For active inequality constraints (those that are enforced as equality constraints
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* in the current working set), we want lambda < 0.
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* This is because:
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* - From the Lagrangian L = f - lambda*c, we know that the constraint force
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* is (lambda * \grad c) = \grad f. Intuitively, to keep the solution x stay
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* on the constraint surface, the constraint force has to balance out with
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* other unconstrained forces that are pulling x towards the unconstrained
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* minimum point. The other unconstrained forces are pulling x toward (-\grad f),
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* hence the constraint force has to be exactly \grad f, so that the total
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* force is 0.
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* - We also know that at the constraint surface c(x)=0, \grad c points towards + (>= 0),
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* while we are solving for - (<=0) constraint.
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* - We want the constraint force (lambda * \grad c) to pull x towards the - (<=0) direction
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* i.e., the opposite direction of \grad c where the inequality constraint <=0 is satisfied.
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* That means we want lambda < 0.
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* - This is because when the constrained force pulls x towards the infeasible region (+),
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* the unconstrained force is pulling x towards the opposite direction into
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* the feasible region (again because the total force has to be 0 to make x stay still)
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* So we can drop this constraint to have a lower error but feasible solution.
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*
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* In short, active inequality constraints with lambda > 0 are BAD, because they
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* violate the condition to be active.
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*
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* And we want to remove the worst one with the largest lambda from the active set.
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*
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*/
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int identifyLeavingConstraint(const InequalityFactorGraph& workingSet,
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const VectorValues& lambdas) const {
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int worstFactorIx = -1;
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// preset the maxLambda to 0.0: if lambda is <= 0.0, the constraint is
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// either
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// inactive or a good inequality constraint, so we don't care!
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double maxLambda = 0.0;
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for (size_t factorIx = 0; factorIx < workingSet.size(); ++factorIx) {
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const LinearInequality::shared_ptr& factor = workingSet.at(factorIx);
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if (factor->active()) {
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double lambda = lambdas.at(factor->dualKey())[0];
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if (lambda > maxLambda) {
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worstFactorIx = factorIx;
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maxLambda = lambda;
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}
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}
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}
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return worstFactorIx;
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}
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/// TODO: comment
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GaussianFactorGraph::shared_ptr buildDualGraph(
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const InequalityFactorGraph& workingSet,
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const VectorValues& delta) const {
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GaussianFactorGraph::shared_ptr dualGraph(new GaussianFactorGraph());
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BOOST_FOREACH (Key key, constrainedKeys_) {
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// Each constrained key becomes a factor in the dual graph
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JacobianFactor::shared_ptr dualFactor =
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createDualFactor(key, workingSet, delta);
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if (!dualFactor->empty()) dualGraph->push_back(dualFactor);
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}
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return dualGraph;
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}
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protected:
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ActiveSetSolver() : constrainedKeys_() {}
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/**
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* Compute step size alpha for the new solution x' = xk + alpha*p, where alpha \in [0,1]
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*
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* @return a tuple of (alpha, factorIndex, sigmaIndex) where (factorIndex, sigmaIndex)
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* is the constraint that has minimum alpha, or (-1,-1) if alpha = 1.
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* This constraint will be added to the working set and become active
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* in the next iteration.
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*/
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boost::tuple<double, int> computeStepSize(
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const InequalityFactorGraph& workingSet, const VectorValues& xk,
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const VectorValues& p, const double& startAlpha) const {
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double minAlpha = startAlpha;
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int closestFactorIx = -1;
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for (size_t factorIx = 0; factorIx < workingSet.size(); ++factorIx) {
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const LinearInequality::shared_ptr& factor = workingSet.at(factorIx);
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double b = factor->getb()[0];
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// only check inactive factors
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if (!factor->active()) {
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// Compute a'*p
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double aTp = factor->dotProductRow(p);
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// Check if a'*p >0. Don't care if it's not.
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if (aTp <= 0)
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continue;
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// Compute a'*xk
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double aTx = factor->dotProductRow(xk);
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// alpha = (b - a'*xk) / (a'*p)
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double alpha = (b - aTx) / aTp;
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// We want the minimum of all those max alphas
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if (alpha < minAlpha) {
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closestFactorIx = factorIx;
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minAlpha = alpha;
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}
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}
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}
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return boost::make_tuple(minAlpha, closestFactorIx);
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}
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};
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} // namespace gtsam
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