small notation change
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@ -2046,7 +2046,7 @@ The adjoint is
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\begin_inset Formula
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\begin_inset Formula
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\begin{eqnarray}
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\begin{eqnarray}
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\Ad T{\xihat} & = & T\xihat T^{-1}\nonumber \\
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\Ad T{\xihat} & = & T\xihat T^{-1}\nonumber \\
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& = & \left[\begin{array}{cc}
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& = & =\left[\begin{array}{cc}
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R & t\\
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R & t\\
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0 & 1
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0 & 1
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\end{array}\right]\left[\begin{array}{cc}
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\end{array}\right]\left[\begin{array}{cc}
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@ -2061,7 +2061,7 @@ R^{T} & -R^{T}t\\
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0 & 0
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0 & 0
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\end{array}\right]\nonumber \\
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\end{array}\right]\nonumber \\
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& = & \left[\begin{array}{cc}
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& = & \left[\begin{array}{cc}
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\skew{\omega} & Rv-\omega R_{\pi/2}t\\
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\skew{\omega} & Rv-t^{\perp}\omega\\
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0 & 0
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0 & 0
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\end{array}\right]\label{eq:adjointSE2}
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\end{array}\right]\label{eq:adjointSE2}
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\end{eqnarray}
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\end{eqnarray}
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@ -2075,7 +2075,7 @@ From this we can express the Adjoint map in terms of plane twist coordinates:
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v'\\
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v'\\
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\omega'
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\omega'
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\end{array}\right]=\left[\begin{array}{cc}
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\end{array}\right]=\left[\begin{array}{cc}
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R & -R_{\pi/2}t\\
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R & -t^{\perp}\\
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0 & 1
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0 & 1
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\end{array}\right]\left[\begin{array}{c}
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\end{array}\right]\left[\begin{array}{c}
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v\\
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v\\
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