inverse action, much nicer
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doc/math.lyx
63
doc/math.lyx
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@ -54,7 +54,7 @@ Geometry Derivatives and Other Hairy Math
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Frank Dellaert
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Frank Dellaert
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\begin_layout Plain Layout
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\begin_layout Standard
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\begin_inset Box Frameless
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\begin_inset Box Frameless
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position "t"
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position "t"
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hor_pos "c"
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hor_pos "c"
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@ -326,7 +326,7 @@ Derivatives of Lie Group Mappings
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\end_layout
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\begin_layout Subsection
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\begin_layout Subsection
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New
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Homomorphisms
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\end_layout
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\begin_layout Standard
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\begin_layout Standard
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@ -410,6 +410,10 @@ e^{-\xhat}=\left(e^{-\xhat}\right)^{-1}\]
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\end_layout
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\begin_layout Standard
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\begin_layout Standard
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\begin_inset Note Note
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status open
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\begin_layout Plain Layout
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Let us define two mappings
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Let us define two mappings
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\begin_inset Formula \[
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\begin_inset Formula \[
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\Phi_{1}(A)=AB\mbox{ and }\Phi_{2}(B)=AB\]
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\Phi_{1}(A)=AB\mbox{ and }\Phi_{2}(B)=AB\]
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@ -423,10 +427,15 @@ Then
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\end_inset
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\end_inset
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\end_layout
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\end_layout
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\begin_layout Subsection
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\begin_layout Subsection
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Old
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Derivatives
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\end_layout
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\begin_layout Standard
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\begin_layout Standard
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@ -903,28 +912,22 @@ we would now like to know what an incremental action
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\begin_inset Formula \begin{eqnarray*}
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\begin_inset Formula \begin{eqnarray*}
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q(x) & = & \left(Te^{\xhat}\right)^{-1}p\\
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q(x) & = & \left(Te^{\xhat}\right)^{-1}p\\
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& = & e^{-\xhat}T^{-1}p\\
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& = & e^{-\xhat}T^{-1}p\\
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& = & T^{-1}Te^{-\xhat}T^{-1}p\\
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& = & e^{-\xhat}q\\
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& = & -T^{-1}\exp\left(T\xhat T^{-1}\right)p\end{eqnarray*}
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& \approx & q-\xhat q\end{eqnarray*}
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\end_inset
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\end_inset
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Hence
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Hence
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\begin_inset Formula \begin{equation}
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\begin_inset Formula \begin{equation}
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\deriv{q(x)}x=-T^{-1}\deriv{\left(T\xhat T^{-1}\mbox{ }p\right)}x\label{eq:inverseAction}\end{equation}
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\deriv{q(x)}x=\deriv{\left(q-\xhat q\right)}x=-\deriv{\left(\xhat q\right)}x=-H_{q}\label{eq:inverseAction}\end{equation}
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\end_inset
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The derivative in
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where
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\begin_inset Formula $p$
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\begin_inset Formula $H_{q}$
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\end_inset
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is again easy for matrix Lie groups:
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will be as above.
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\begin_inset Formula \[
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\deriv{\left(T^{-1}p\right)}p=T^{-1}\]
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\end_inset
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\end_layout
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\end_layout
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\begin_layout Section
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\begin_layout Section
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@ -1679,6 +1682,36 @@ in homogenous coordinates.
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\end_inset
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\end_inset
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The derivative of the inverse action
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\begin_inset Formula $T^{-1}p$
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\end_inset
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is given by formula
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\begin_inset CommandInset ref
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LatexCommand ref
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reference "eq:inverseAction"
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\end_inset
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:
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\begin_layout Standard
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\family roman
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\series medium
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\shape up
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\size normal
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\emph off
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\bar no
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\noun off
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\color none
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\begin_inset Formula \[
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\deriv{\hat{q}(\xi)}{\xi}=-H_{q}=\left[\begin{array}{cc}
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\Skew q & -I_{3}\end{array}\right]\]
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\end_inset
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\end_layout
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\end_layout
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